Friday, December 20, 2013

Experiment

Kevin Melanio 12-23-10 skittles Experiment The purposes of this audition is to learn ab proscribed the exponential function exploitation and decay. Exponential growth and decay is repeated multiplication. This experiment shows how a cc skittles in a theme office groundwork be exponential decay as you shake it and sway the 4 sections that is marked with an x. put give | Number of Skittles | Percentage of # of skittles | 0 | 200 | 0.61 | 1 | 122 | 0.63 | 2 | 77 | 0.69 | 3 | 53 | 0.58 | 4 | 31 | 0.52 | 5 | 16 | 0.06 | 6 | 1 | 0 | 7 | 0 | 0 | Average: .38 I got this frame by adding the division and dual-lane by the total emergence of stage. The average share should be a quarter of deoxycytidine monophosphate portion. The reason that the percent is way off we didnt shoo k it right and the lines that divided the plate is not equal to each other. Stage Number | Number of Skittles | Percentage of # of skittles | 0 | 20 | 1.45 | 1 | 29 | 1.62 | 2 | 47 | 1.43 | 3 | 67 | 1.39 | 4 | 93 | 1.39 | 5 | 129 | 1.33 | 6 | 172 | 1.
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16 | 7 | 200 | 0 | Average: 1.39 I got this material body by adding the percentage and divided by the total publication of stage. Uo =200 Uo = 20 n ? 1 n ? 1 Un=Un-1 x .38 Un =Un-1 x 1.39 200 is commencem! ent cheer and .38 is the 20 is the startle value and 1.39 is the uniform and thats how some(prenominal) constant and thats how many I took it out everytime I shook it. I took it out everytime I shook it. Y= 200 x .38^x Y= 20 x 1.38^x 200 is the starting value and x 20 is the starting value and x is the stage is the stage number. .38 is how number. 1.38 is the number of how many candies I took it out.candies I added. Experiment I Experiment II Y=a x b^x Y=a x b^x a=315.2579296 a=22.19081766 b=.4746048684 b=1.40187329...If you want to get a full essay, order it on our website: BestEssayCheap.com

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